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🎨 视觉封面LeetCode Remove Duplicates from Sorted List
Problem
Given a sorted linked list, delete all duplicates such that each element appear only once.
For example, Given 1->1->2, return 1->2. Given 1->1->2->3->3, return 1->2->3.
删除链表中值重复的数据。链表指定定义为:
public class ListNode {
int val;
ListNode next;
ListNode(int x) {
val = x;
}
}
Java 实现
package com.coderli.leetcode.algorithms.easy;
/**
* Given a sorted linked list, delete all duplicates such that each element appear only once.
* <p>
* For example,
* Given 1->1->2, return 1->2.
* Given 1->1->2->3->3, return 1->2->3.
*
* @author li.hzh 2017-11-09 12:43
*/
public class RemoveDuplicatesFromSortedList {
public static void main(String[] args) {
RemoveDuplicatesFromSortedList remove = new RemoveDuplicatesFromSortedList();
RemoveDuplicatesFromSortedList.ListNode first = remove.new ListNode(1);
RemoveDuplicatesFromSortedList.ListNode second = remove.new ListNode(1);
first.next = second;
second.next = remove.new ListNode(2);
print(remove.deleteDuplicates(first));
first.next = second;
second.next = remove.new ListNode(1);;
print(remove.deleteDuplicates(first));
}
public ListNode deleteDuplicates(ListNode head) {
if (head == null) {
return head;
}
ListNode currentNode = head;
ListNode preNode = null;
while (currentNode != null) {
if (preNode == null) {
preNode = currentNode;
} else {
if (preNode.val == currentNode.val) {
preNode.next = currentNode.next;
} else {
preNode = currentNode;
}
}
currentNode = currentNode.next;
}
return head;
}
public class ListNode {
int val;
ListNode next;
ListNode(int x) {
val = x;
}
}
private static void print(RemoveDuplicatesFromSortedList.ListNode list) {
while (list != null) {
System.out.println(list.val);
list = list.next;
}
}
}
分析
没什么可过多解释的,保持好中间状态即可。
所有代码开源上传至 GitHub:yummy-code 仓库 · GESP 专题站:GESP WIKI
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一个中年人的自留地,记录学习 C++、GESP/NOI、Java、Python 与算法架构的心得体会。本站唯一网址:coderli.com