数据结构与算法
双指针、回溯剪枝、图论与搜索
🎨 视觉封面LeetCode Second Highest Salary
Problem
Write a SQL query to get the second highest salary from the Employee table.
+----+--------+
| Id | Salary |
+----+--------+
| 1 | 100 |
| 2 | 200 |
| 3 | 300 |
+----+--------+
For example, given the above Employee table, the query should return 200 as the second highest salary. If there is no second highest salary, then the query should return null.
+---------------------+
| SecondHighestSalary |
+---------------------+
| 200 |
+---------------------+
即找到第二大的元素。没有返回null。
MySQL
# Write your MySQL query statement below
SELECT (SELECT DISTINCT Salary FROM Employee ORDER BY Salary DESC LIMIT 1 OFFSET 1) AS SecondHighestSalary;
分析
通过LIMIT OFFSET找到第二个元素。DISTINCT是为了排除两个最大值的情况。嵌套是为了解返回null的情况。另一种办法是使用IFNULL函数。
所有代码开源上传至 GitHub:yummy-code 仓库 · GESP 专题站:GESP WIKI
欢迎加入:C++ GESP/CSP 考级答疑群(688906745) 与 Java/Python交流群(982860385),点击可直接加群。
猜你想读 · 相关文章推荐
LeetCode Combine Two Tables
Problem Table: Person Table: Address Write a SQL query for a report that provides the following information for each person in the Person table, regardless if t...
LeetCode Customers Who Never Order
Problem Suppose that a website contains two tables, the Customers table and the Orders table. Write a SQL query to find all customers who never order anything....
LeetCode Duplicate Emails
Problem Write a SQL query to find all duplicate emails in a table named Person. For example, your query should return the following for the above table: 找到重复的Em...
OneCoder (lihongzheshuai)
一个中年人的自留地,记录学习 C++、GESP/NOI、Java、Python 与算法架构的心得体会。本站唯一网址:coderli.com